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Solved exercise · level 3 of 5

Force between two charges

Skills: Calculate

Statement

Two point charges q = 5 µC and q' = 6 µC are placed in air 0.5 m apart. Compute the electrostatic force between them (k = 9 × 10⁹ N·m²/C²).

q = 5 µC · q' = 6 µC · d = 0.5 m

Parametric exercise: the values change with every draw; these are one example.

Guided problem in 4 steps: unknown, formula, units, data, result.

1 hint from Bastaya available in the lab
Solution

F = 9 × 10⁹ × 5 × 10⁻⁶ × 6 × 10⁻⁶ / 0.5² = 1.08 N. Convert µC to C before computing.

Course sheet of the chapter : Electrostatics

This chapter is covered by the paths: General electricity

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

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