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Solved exercise · level 2 of 5

Current in series

Skills: Analyse

Statement

R1 = 390 Ω and R2 = 820 Ω in series at 15 V. Current drawn from G?

Parametric exercise: the values change with every draw; these are one example.

2 hints from Bastaya available in the lab
Solution

Req = 390 + 820 = 1.21 kΩ; I = 15 / 1210 = 12.4 mA.

Course sheet of the chapter : Resistor networks

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

Del
delete
R
rotate
C
chip brush
Esc
cancel
wheel
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fit the board
drag background
pan

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