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Solved exercise · level 3 of 5

Resistance and temperature

Skills: Calculate

Statement

A copper winding has a resistance of 47 Ω at 20 °C. What is its resistance at 80 °C? (α = 0.0039 /°C)

R₀ = 47 Ω · θ = 80 °C

Parametric exercise: the values change with every draw; these are one example.

Guided problem in 4 steps: unknown, formula, units, data, result.

1 hint from Bastaya available in the lab
Solution

Δθ = 80 − 20; R = 47 × (1 + 0.0039 × Δθ) = 58 Ω.

Course sheet of the chapter : Ohm's law & resistance

This chapter is covered by the paths: General electricity

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

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