Labo Élec

electrical lab simulator
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Exercise from the chapter "AC power"

Why correct the power factor?

Level 1 of 5 · Skills: Know

Statement

A poor power factor is penalising because...

  1. The line current is larger for the same useful power
  2. The mains voltage increases
  3. The frequency decreases
  4. The active power becomes negative
2 hints from Bastaya available in the lab
Solution

I = P / (U·cos φ): for the same P, a low cos φ means more current, hence more line losses and oversized cables.

Course sheet of the chapter : AC power

This chapter is covered by the paths: General electricity

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Workbench

Circuit diagram CEI 60617

How does it work?

The perfboard: each big hole is a circuit node. You push a single leg of a component (resistor, lamp...) into it. The 4 small holes around it are connected to it: that is where chips and leads plug in.

  1. Drag a component onto the board: it snaps onto the grid. R rotates it.
  2. To join neighbouring big holes, click Jumper chip in the palette (or C) then drag on the board: a line of chips is laid at once. Bridged holes become a single node.
  3. For long links and for the power supply (placed next to the board), drag a lead from one big hole to another (or to a terminal).
  4. As soon as a loop is closed, the circuit is solved in real time (Ohm + Kirchhoff) and the diagram follows.
  5. Zoom with the wheel (or + / −, two-finger pinch); drag the background to pan, 0 fits the board. The + buttons around the board add a row or a column.

Del delete · R rotate · C chip brush · Esc cancel · wheel zoom · drag the background to pan

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