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Solved exercise · level 1 of 5

Why correct the power factor?

Skills: Know

Statement

A poor power factor is penalising because...

  1. The line current is larger for the same useful power
  2. The mains voltage increases
  3. The frequency decreases
  4. The active power becomes negative
2 hints from Bastaya available in the lab
Solution

I = P / (U·cos φ): for the same P, a low cos φ means more current, hence more line losses and oversized cables.

Course sheet of the chapter : AC power

This chapter is covered by the paths: General electricity

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

Del
delete
R
rotate
C
chip brush
Esc
cancel
wheel
zoom
0
fit the board
drag background
pan

Confirmer

Renommer

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