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Solved exercise · level 5 of 5

Real coil and capacitor in parallel

Skills: Calculate

Statement

A coil (R = 60 Ω, L = 0.5 H) is connected in parallel with a 16 µF capacitor. What current does the whole draw at 220 V, 50 Hz?

Parametric exercise: the values change with every draw; these are one example.

2 hints from Bastaya available in the lab
Solution

Coil: Z = 168.1 Ω, I_Z = 1.308 A, cos φ_Z = 0.357, sin φ_Z = 0.934; capacitor: I_C = 1.11 A; I = √((I_Z cos φ_Z)² + (I_Z sin φ_Z − I_C)²) = 0.481 A.

Course sheet of the chapter : RLC circuits

This chapter is covered by the paths: General electricity, ISL-oriented exercises

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

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C
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