Labo Élec
electrical lab simulator
Reminder sheet
Coils and capacitors resist alternating current without heating: they are reactances. Combined with R they form the impedance, which Fresnel draws so well.
In AC a coil and a capacitor oppose the current without dissipating energy: their reactance is X_L = L·ω (grows with f) and X_C = 1/(C·ω) (decreases with f). The current lags the voltage by 90° in a coil, leads by 90° in a capacitor.
The impedance Z (Ω) generalises resistance: U = Z·I. In series, Z = √(R² + (X_L − X_C)²) and tan φ = (X_L − X_C)/R. When X_L = X_C the circuit is at resonance: Z = R, maximum current.
| Quantity | Symbol | Unit |
|---|---|---|
| Reactance | X | Ω |
| Inductance | L | H |
| Capacitance | C | F |
| Angular frequency | ω | rad/s |
| Quantity | Symbol | Unit |
|---|---|---|
| Impedance | Z | Ω |
| Resistance | R | Ω |
| Quantity | Symbol | Unit |
|---|---|---|
| RMS voltage | U | V |
| RMS current | I | A |
| Quantity | Symbol | Unit |
|---|---|---|
| Phase shift | φ | rad |
A series circuit R = 100 Ω, L = 0.2 H, C = 20 µF is supplied at 230 V, 50 Hz. Find the reactances, the impedance, the current and the phase shift.
ω = 2π × 50 = 314 rad/s.
X_L = L · ω = 0.2 × 314 = 62.8 Ω; X_C = 1 / (C · ω) = 1 / (20 × 10⁻⁶ × 314) = 159 Ω.
Z = √(R² + (X_L − X_C)²) = √(100² + (−96.2)²) = 139 Ω.
I = U / Z = 230 / 139 = 1.66 A.
tan φ = (X_L − X_C) / R = −0.962 → φ = −44°: X_C dominates, the circuit is capacitive, the current leads the voltage.
Impedance triangle: Z² = R² + (X_L − X_C)².