Elec Class

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Solved exercise · level 3 of 5

Resistors given by their rating

Skills: Calculate

Statement

At 12 V, three loads are in parallel: R₁ = 12 Ω, R₂ drawing 2 A, and R₃ absorbing 65.5 W. What is the equivalent resistance?

U = 12 V · R₁ = 12 Ω · I₂ = 2 A · P₃ = 65.5 W

Parametric exercise: the values change with every draw; these are one example.

Guided problem in 4 steps: unknown, formula, units, data, result.

1 hint from Bastaya available in the lab
Solution

R₂ = U / I₂ = 6 Ω; R₃ = U² / P₃ = 2.2 Ω; 1/Req = 1/12 + 1/6 + 1/2.2 → Req = 1.42 Ω.

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

Del
delete
R
rotate
C
chip brush
Esc
cancel
wheel
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fit the board
drag background
pan

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