Elec Class

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Solved exercise · level 3 of 5

No load, then under load

Skills: Measure, Calculate

Statement

K1 is open: source G delivers no current. V1 then measures its no-load voltage, i.e. its EMF. Note it.

Parametric exercise: the values change with every draw; these are one example.

1 hint from Bastaya available in the lab
Solution

No load U = E = 6 V; under load U = E − r·I = 4.64 V; r = (E − U) / I = 2 Ω. This is the classic way to measure r.

Course sheet of the chapter : Real generators & loads

This chapter is covered by the paths: General electricity, Measurement prep, ISL-oriented exercises

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

Del
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R
rotate
C
chip brush
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drag background
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