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Solved exercise · level 2 of 5

Two cells in series

Skills: Analyse

Statement

Two cells E1 = 4.5 V and E2 = 4.5 V are in series (the − of one on the + of the other) and supply R1 = 47 Ω.

What current flows?

Parametric exercise: the values change with every draw; these are one example.

2 hints from Bastaya available in the lab
Solution

Loop rule: E1 + E2 − R1·I = 0 → I = (4.5 + 4.5) / 47 = 191 mA.

Course sheet of the chapter : Kirchhoff's laws

This chapter is covered by the paths: General electricity, Measurement prep

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

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C
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