Labo Élec
electrical lab simulator
Reminder sheet
Changing the flux through a coil gives birth to a voltage: that is induction. Lenz adds that the effect always opposes its cause.
Faraday: any change of magnetic flux through a circuit induces an EMF E = −N·ΔΦ/Δt. Lenz: the induced current opposes the cause producing it (minus sign). A conductor cutting field lines at speed v gets E = B·l·v.
Self-induction: a coil opposes changes of its own current, E = −L·ΔI/Δt; L is the inductance, in henries. It stores W = ½ L I². When an inductive circuit is opened, the overvoltage strikes an arc: it is suppressed by a diode or an RC network.
| Quantity | Symbol | Unit |
|---|---|---|
| Induced EMF | E | V |
| Number of turns | N | - |
| Flux | Φ | Wb |
| Time | t | s |
| Quantity | Symbol | Unit |
|---|---|---|
| Magnetic flux density | B | T |
| Length | l | m |
| Speed | v | m/s |
| Quantity | Symbol | Unit |
|---|---|---|
| Inductance | L | H |
| Current | I | A |
| Quantity | Symbol | Unit |
|---|---|---|
| Energy | W | J |
| Quantity | Symbol | Unit |
|---|---|---|
| Time constant | τ | s |
The flux through a 200-turn coil drops from 2 mWb to 0 in 10 ms: what induced EMF? A coil L = 0.5 H carrying 2 A: what energy does it store, and what voltage appears if the current is cut in 1 ms?
E = N · ΔΦ / Δt = 200 × 2 × 10⁻³ / 10 × 10⁻³ = 40 V (Lenz's minus sign only gives the direction: the induced current opposes the disappearance of the flux).
W = ½ · L · I² = 0.5 × 0.5 × 4 = 1 J.
E = L · ΔI / Δt = 0.5 × 2 / 10⁻³ = 1 000 V: hence the arc when an inductive circuit is opened, and the freewheeling diode that suppresses it.
Lenz: as the north approaches, the loop creates a north facing the magnet to repel it.