Elec Class

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Solved exercise · level 5 of 5

Primary current from the secondary EMF

Skills: Calculate

Statement

A coil 80 cm long with an inner cross-section of 8 cm² has 2000 turns; a second winding of 400 turns is wound over it. What current is needed in the first one to produce, by cutting it in 20 ms, an EMF of 22.9 mV across the 400 turns?

Parametric exercise: the values change with every draw; these are one example.

2 hints from Bastaya available in the lab
Solution

E = N₂ · B · S / Δt → B = E · Δt / (N₂ · S) = 0.00143 T; then B = 4π·10⁻⁷ · N₁ · I / l → I = B · l / (4π·10⁻⁷ · N₁) = 0.455 A.

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

Del
delete
R
rotate
C
chip brush
Esc
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drag background
pan

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