Elec Class

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Solved exercise · level 5 of 5

Two-source ladder

Skills: Analyse, Calculate

Statement

Two sources (E1 = 24 V on the left, G = 46 V on the right, + at the bottom) and six resistors: R1 = 4 Ω, R2 = 4 Ω, R3 = 2 Ω on top, R4 = 3 Ω and R5 = 5 Ω as rungs, R6 = 2 Ω at the bottom. Three loops, two junctions: compute the current in R1.

Parametric exercise: the values change with every draw; these are one example.

2 hints from Bastaya available in the lab
Solution

Solved by loops or junctions: I₁ = 5.45 A, I₂ = 4.72 A, I₃ = 9.94 A, I₄ = 732 mA, I₅ = 5.22 A, I₆ = 4.72 A. At the junctions: I₁ = I₂ + I₄ and I₃ = I₂ + I₅.

Other exercises of the chapter

Simulated time00:00:00
Q = I·t-
W = P·t-

Circuit diagram CEI 60617

How does it work?

Each big hole is a circuit node: you push one leg of a component into it. The 4 small holes around it are connected to it: chips and leads plug in there.

  1. Place a component Drag it from the palette: it snaps onto the grid. R rotates it.
  2. Bridge neighbouring holes Pick the jumper chip (or C) and drag on the board: bridged holes become a single node.
  3. Draw a lead For long links and the power supply: from one big hole to another, or to a terminal.
  4. Close the loop The circuit is solved live (Ohm, Kirchhoff) and the diagram follows.

Shortcuts

Del
delete
R
rotate
C
chip brush
Esc
cancel
wheel
zoom
0
fit the board
drag background
pan

Confirmer

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